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Exercise 2 - integer to binary

Here is my algorithm in C to convert an integer to a binary number:

# include \u0026lt;stdio.h>
# include \u0026lt;math.h>
# include \u0026lt;stdlib.h>

main () {

int num1, i = 0, choice;
double base = pow (2, i);

printf ("Enter an integer to convert Binary: ");
scanf ("% d ", & num1);

while (base<=num1)
    {
          printf(" %lf", base);
          i++;
          base= pow(2,i);
    }
    i--;
    printf("\n i=%d\n\n", i);
    base= pow(2,i);
   
    while (num1>0)
    {
    if (base
    {
                  num1-=base;
                  i--;
                  base= pow(2,i);
                  printf("1");
    }
    else if (base>num1)
    {
        i--;
        base= pow(2,i);
        printf("0");
    }
    else if (base=num1)
    {
    num1-=base;
    printf("1");
    while (i>0)
    {
          printf("0");
          i--;
    }
    }
    }

    printf("\n\n.");
    system("pause");
    return 0;}

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Exercise 1 - Creating

First we make a pseudocode similar to this to guide us through the class:

count = 0 a = 0 p = 1

print 0.1
while (count \u0026lt;100)
do
n = a + p
print n
a = p, p = n count + +

An algorithm in C would look like:

# include \u0026lt;stdio.h>
# include \u0026lt;stdlib.h>

main () {

/ * Defining variables, C is a numerical count * /
int A = 0, B = 1, C = 3, N;
printf ("% d \\ n% d \\ n", A, B )
while (C \u0026lt;= 47)
{N = A + B;
printf ("% ld \\ n", N);
/ * the numbers are run on the variables * /
A = B, B = N;
/ * Increase the count * /
C++;
          }
system ("pause");
}